Already a member?
Sign in
Ohm's Law
How Ohm's Law shaped Edison's design for the light bulb and associated systems? (Jonnes 59-60)
Edison wanted to create an incandescent light bulb with a high resistance filament. This was leaning away from what other scientists were working on at the time. The problem Edison found with a high resistance filament, was that it would cost corporations too much money to produce, so he had to change his production to a path of low resistance. To keep costs low, Edison finalized his invention with running a low current through a very thin copper wire.
Edison was aware of Ohms law which stated that the potential differnece, also known as voltage, across a conductor has a proportional constant with a current running through it.
Ohm's Law
Voltage(V) = Current (I) * Resistance (R)Electric current is measured in ampheres. Voltage is measured in volts. Resistance is measured in ohms.
According to Jill Hones, Edison made a dececision to run a low current (I) being between one and two amps. Because of this he had to use a high resistance light bulb of 220 ohms with a low voltage around 110 volts. This doesn't add up correctly to make the equation work because 110 does not equal 220 * 1. Because this equation does not add up, Jones may have gotten her facts up. Or with this primitive lightbulb the resistance may not have all been caught by the current.
Edison wanted to create an incandescent light bulb with a high resistance filament. This was leaning away from what other scientists were working on at the time. The problem Edison found with a high resistance filament, was that it would cost corporations too much money to produce, so he had to change his production to a path of low resistance. To keep costs low, Edison finalized his invention with running a low current through a very thin copper wire.
Edison was aware of Ohms law which stated that the potential differnece, also known as voltage, across a conductor has a proportional constant with a current running through it.
Ohm's Law
Voltage(V) = Current (I) * Resistance (R)
According to Jill Hones, Edison made a dececision to run a low current (I) being between one and two amps. Because of this he had to use a high resistance light bulb of 220 ohms with a low voltage around 110 volts. This doesn't add up correctly to make the equation work because 110 does not equal 220 * 1. Because this equation does not add up, Jones may have gotten her facts up. Or with this primitive lightbulb the resistance may not have all been caught by the current.
gayers |
Latest page update: made by gayers
, Sep 20 2007, 6:09 PM EDT
(about this update
About This Update
Edited by gayers
view changes - complete history) |
|
Keyword tags:
None
More Info: links to this page
|